61 lines
1.7 KiB
SQL
61 lines
1.7 KiB
SQL
-- 用途：
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-- 1) 清空所有学生的住宿信息
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-- 2) 将学籍状态为“在读(student_status=1)”的学生统一标记为“申请床位(is_boarder=1)”
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--
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-- 依据代码：
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-- - 批量申请床位逻辑：xg_student_msg.is_boarder = 1
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-- - 学籍状态在读：xg_student_msg.student_status = '1'
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--
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-- 执行前建议：
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-- - 先在测试环境验证
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-- - 如需限制租户，可在每条SQL追加: AND tenant_id = 0
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START TRANSACTION;
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-- =========================
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-- Step 1: 删除/清空住宿信息
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-- =========================
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-- 1.1 清空学生表中的住宿字段，同时重置是否住校
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UPDATE xg_student_msg
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SET
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dormitory_building = NULL,
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dormitory_room = NULL,
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ext_field1 = NULL, -- 床位ID
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is_boarder = 0,
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update_time = NOW()
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WHERE deleted = 0;
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-- 1.2 逻辑删除床位-学生分配关系（相当于删除住宿分配记录）
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UPDATE xg_dorm_bed_student
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SET
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deleted = '1',
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update_time = NOW()
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WHERE deleted = '0';
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-- 1.3 重置床位状态为空闲
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UPDATE xg_dorm_bed
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SET
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bed_status = '0',
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update_time = NOW()
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WHERE deleted = '0';
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-- =========================
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-- Step 2: 在读学生统一申请床位
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-- =========================
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-- 系统“批量申请床位”对应逻辑：仅更新 is_boarder = 1
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UPDATE xg_student_msg
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SET
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is_boarder = 1,
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update_time = NOW()
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WHERE deleted = 0
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AND student_status = '1';
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COMMIT;
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-- 可选核对SQL（执行后可单独运行）
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-- SELECT COUNT(1) AS boarding_apply_count FROM xg_student_msg WHERE deleted = 0 AND student_status = '1' AND is_boarder = 1;
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-- SELECT COUNT(1) AS active_bed_rel_count FROM xg_dorm_bed_student WHERE deleted = '0';
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-- SELECT COUNT(1) AS occupied_bed_count FROM xg_dorm_bed WHERE deleted = '0' AND bed_status = '1';
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