88 lines
2.4 KiB
SQL
88 lines
2.4 KiB
SQL
-- ==========================================
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-- 修复项目申报中申请人ID为空的问题
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-- 创建时间: 2025-08-01
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-- 描述: 检查并修复cw_project_application表中applicant_id为NULL的记录
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-- ==========================================
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-- 1. 检查问题记录
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SELECT
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id,
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application_no,
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project_name,
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applicant_id,
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applicant_name,
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department_id,
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department_name,
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approval_status,
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create_by,
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create_time
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FROM cw_project_application
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WHERE applicant_id IS NULL OR applicant_id = 0;
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-- 2. 修复方案1：将申请人ID设置为创建者ID（推荐）
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UPDATE cw_project_application
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SET
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applicant_id = create_by,
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applicant_name = (
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SELECT nick_name
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FROM sys_user
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WHERE user_id = cw_project_application.create_by
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AND deleted = 0
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LIMIT 1
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)
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WHERE (applicant_id IS NULL OR applicant_id = 0)
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AND create_by IS NOT NULL
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AND create_by > 0;
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-- 3. 修复方案2：如果创建者也为空，设置为系统管理员（ID=1）
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UPDATE cw_project_application
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SET
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applicant_id = 1,
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applicant_name = '系统管理员'
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WHERE (applicant_id IS NULL OR applicant_id = 0)
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AND (create_by IS NULL OR create_by = 0);
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-- 4. 修复部门信息为空的记录
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UPDATE cw_project_application
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SET
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department_id = (
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SELECT dept_id
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FROM sys_user
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WHERE user_id = cw_project_application.applicant_id
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AND deleted = 0
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LIMIT 1
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),
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department_name = (
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SELECT d.dept_name
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FROM sys_user u
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LEFT JOIN sys_dept d ON u.dept_id = d.dept_id
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WHERE u.user_id = cw_project_application.applicant_id
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AND u.deleted = 0
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AND d.deleted = 0
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LIMIT 1
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)
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WHERE (department_id IS NULL OR department_id = 0)
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AND applicant_id IS NOT NULL
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AND applicant_id > 0;
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-- 5. 验证修复结果
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SELECT
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'修复后检查' as check_type,
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COUNT(*) as total_records,
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SUM(CASE WHEN applicant_id IS NULL OR applicant_id = 0 THEN 1 ELSE 0 END) as null_applicant_count,
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SUM(CASE WHEN department_id IS NULL OR department_id = 0 THEN 1 ELSE 0 END) as null_department_count
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FROM cw_project_application;
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-- 6. 显示修复后的记录
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SELECT
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id,
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application_no,
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project_name,
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applicant_id,
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applicant_name,
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department_id,
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department_name,
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approval_status
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FROM cw_project_application
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ORDER BY create_time DESC
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LIMIT 10; |