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docs/sql/migrations/2026-08-03-crm-contract-no-check-duplicates.sql

@@ -1,56 +0,0 @@
--- 合同编号重复排查（只读，不改数据）
--- 库：shanxia2.0 / crm_contract
--- 用途：检查租户内 contract_no 是否仍有重复（含软删）
-
-SET NAMES utf8mb4;
-
--- 1) 按 (contract_no, tenant_no) 分组：任何重复（含软删）
-SELECT
-  contract_no,
-  tenant_no,
-  COUNT(*) AS cnt,
-  SUM(CASE WHEN del_flag = 0 THEN 1 ELSE 0 END) AS alive_cnt,
-  SUM(CASE WHEN del_flag = 1 THEN 1 ELSE 0 END) AS deleted_cnt,
-  GROUP_CONCAT(
-    CONCAT(id, '/del', del_flag, '/', IFNULL(customer_name, ''))
-    ORDER BY del_flag, create_time
-    SEPARATOR ' | '
-  ) AS detail
-FROM crm_contract
-GROUP BY contract_no, tenant_no
-HAVING COUNT(*) > 1
-ORDER BY cnt DESC, contract_no;
-
--- 2) 仅有效单据 (del_flag=0) 是否撞号
-SELECT
-  contract_no,
-  tenant_no,
-  COUNT(*) AS alive_cnt,
-  GROUP_CONCAT(id ORDER BY create_time SEPARATOR ' | ') AS ids,
-  GROUP_CONCAT(IFNULL(customer_name, '') ORDER BY create_time SEPARATOR ' | ') AS customers
-FROM crm_contract
-WHERE del_flag = 0
-GROUP BY contract_no, tenant_no
-HAVING COUNT(*) > 1
-ORDER BY alive_cnt DESC, contract_no;
-
--- 3) 指定编号示例：SX/X-JT20260803001（含改号后的 ~DEL~ 变体）
-SELECT
-  id,
-  contract_no,
-  contract_name,
-  customer_name,
-  status,
-  del_flag,
-  create_time,
-  update_time
-FROM crm_contract
-WHERE tenant_no = 'shanxia2.0'
-  AND (
-    contract_no = 'SX/X-JT20260803001'
-    OR contract_no LIKE 'SX/X-JT20260803001~%'
-  )
-ORDER BY del_flag, create_time;
-
--- 4) 当前唯一索引是否已是全局唯一版
-SHOW INDEX FROM crm_contract WHERE Key_name LIKE 'uk_contract%';

docs/sql/migrations/2026-08-03-crm-contract-no-global-unique.sql

@@ -1,77 +0,0 @@
--- 合同编号租户内全局唯一（含软删不复用）— 可重复执行
--- 1) 消解已有 (contract_no, tenant_no) 撞号：保留 del_flag=0，软删行改号
--- 2) 唯一索引改为 (contract_no, tenant_no)
---
--- 说明：若生产已执行过，旧索引 uk_contract_tenant_no_del 可能已不存在，
---      本脚本会先检查再 DROP/ADD，避免 1091。
-
-SET NAMES utf8mb4;
-
--- 软删撞号改号：{原编号}~DEL~{id前8位}
-UPDATE crm_contract c
-INNER JOIN (
-  SELECT contract_no, tenant_no
-  FROM crm_contract
-  GROUP BY contract_no, tenant_no
-  HAVING COUNT(*) > 1
-) d ON c.contract_no = d.contract_no AND c.tenant_no = d.tenant_no
-SET c.contract_no = CONCAT(c.contract_no, '~DEL~', LEFT(c.id, 8)),
-    c.update_time = NOW()
-WHERE c.del_flag = 1
-  AND c.contract_no NOT LIKE '%~DEL~%'
-  AND c.contract_no NOT LIKE '%~DUP~%';
-
--- 若仍有撞号（极端：两条都 del_flag=0），再改非 keep 的一条
-UPDATE crm_contract c
-INNER JOIN (
-  SELECT contract_no, tenant_no, MIN(id) AS keep_id
-  FROM crm_contract
-  GROUP BY contract_no, tenant_no
-  HAVING COUNT(*) > 1
-) d ON c.contract_no = d.contract_no AND c.tenant_no = d.tenant_no AND c.id <> d.keep_id
-SET c.contract_no = CONCAT(c.contract_no, '~DUP~', LEFT(c.id, 8)),
-    c.update_time = NOW()
-WHERE c.contract_no NOT LIKE '%~DUP~%';
-
--- 有旧索引则删除
-SET @db := DATABASE();
-SET @sql := (
-  SELECT IF(
-    EXISTS(
-      SELECT 1 FROM information_schema.statistics
-      WHERE table_schema = @db
-        AND table_name = 'crm_contract'
-        AND index_name = 'uk_contract_tenant_no_del'
-    ),
-    'ALTER TABLE crm_contract DROP INDEX `uk_contract_tenant_no_del`',
-    'SELECT ''skip DROP uk_contract_tenant_no_del'' AS info'
-  )
-);
-PREPARE stmt FROM @sql;
-EXECUTE stmt;
-DEALLOCATE PREPARE stmt;
-
--- 无新索引则添加
-SET @sql := (
-  SELECT IF(
-    EXISTS(
-      SELECT 1 FROM information_schema.statistics
-      WHERE table_schema = @db
-        AND table_name = 'crm_contract'
-        AND index_name = 'uk_contract_tenant_no'
-    ),
-    'SELECT ''skip ADD uk_contract_tenant_no (already exists)'' AS info',
-    'ALTER TABLE crm_contract ADD UNIQUE KEY `uk_contract_tenant_no` (`contract_no`, `tenant_no`)'
-  )
-);
-PREPARE stmt FROM @sql;
-EXECUTE stmt;
-DEALLOCATE PREPARE stmt;
-
--- 验收：应为空
-SELECT contract_no, tenant_no, COUNT(*) AS cnt
-FROM crm_contract
-GROUP BY contract_no, tenant_no
-HAVING COUNT(*) > 1;
-
-SHOW INDEX FROM crm_contract WHERE Key_name LIKE 'uk_contract%';