60 lines
2.2 KiB
Python
60 lines
2.2 KiB
Python
"""菜单 code 权限守卫（V0.3：通过 sys_user_role → sys_role_menu → sys_menu.perms）"""
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from typing import Any, Callable, Dict, Iterable, Set
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from fastapi import Depends, HTTPException
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from sqlalchemy.orm import Session
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from app.core.auth import get_current_user
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from app.services.web_auth_roles import iter_user_menu_perm_codes
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ADMIN_ROLES = {"admin", "super_admin"}
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SUPER_ADMIN_ROLE = "super_admin"
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def require_admin_or_super_admin(current_user: dict = Depends(get_current_user)):
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"""运营端角色守卫：admin / super_admin 可访问。"""
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role = current_user.get("role")
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if role not in ADMIN_ROLES:
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raise HTTPException(status_code=403, detail="需要运营人员权限")
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return current_user
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def get_user_menu_codes(db: Session, user_id: str) -> Set[str]:
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"""读取用户授权的菜单权限标识集合（与前端 meta.menuCode / perms 对齐）。"""
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return iter_user_menu_perm_codes(db, user_id or "")
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def user_has_menu_perm(db: Session, user: dict, perm_code: str) -> bool:
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"""判断用户是否拥有指定权限码（不拦截请求，用于字段/按钮级能力控制）。"""
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code = (perm_code or "").strip()
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if not code:
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return False
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if user.get("role") == SUPER_ADMIN_ROLE:
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return True
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user_id = (user.get("user_id") or "").strip()
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if not user_id:
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return False
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return code in get_user_menu_codes(db, user_id)
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def strip_row_fields(rows: Iterable[Dict[str, Any]], *field_names: str) -> None:
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"""从响应行中移除敏感字段（原地修改）。"""
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keys = [k for k in field_names if k]
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if not keys:
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return
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for row in rows:
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for key in keys:
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row.pop(key, None)
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def require_menu_code(menu_code: str) -> Callable:
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"""接口菜单权限守卫（已统一放行 menuCode 校验，仅保留运营端登录）。"""
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_ = menu_code # 保留参数以兼容各路由 Depends(require_menu_code("..."))
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return require_admin_or_super_admin
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def require_any_menu_code(*menu_codes: str) -> Callable:
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"""接口菜单权限守卫（已统一放行 menuCode 校验，仅保留运营端登录）。"""
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_ = menu_codes
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return require_admin_or_super_admin
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